你没发现这是个 if statement，后面的 (setq foo (cons '("a" . "this is a") foo)) 不执行吗
问个语法问题
(let ((load-path-list
'(
"~/.emacs.d.customize/emacs-libvterm"
"~/.emacs.d.customize/customs"
)))
(setq load-path (append load-path load-path-list)))
由于 "~/.emacs.d.customize/emacs-libvterm"这个字符串，我在别的地方还要用，所以就改成下面的写法
(let* ((libvterm-dir "~/.emacs.d.customize/emacs-libvterm")
(load-path-list
'(
libvterm-dir
"~/.emacs.d.customize/customs"
)))
(setq load-path (append load-path load-path-list))
(if (file-directory-p libvterm-dir)
(let (vterm-install)
(require 'vterm))))
libvterm-dir在load-path-list里没展开，该怎么改？
`(,libvterm-dir "~/.emacs.d.customize/customs")
或者用list函数构建列表
(list libvterm-dir "~/.emacs.d.customize/customs")
哦，想起来了。
另外宏里，是这么的写法
`(,xxx ....)
宏之外用
'(,xxx ....)
为什么要分`和‘
,和,@都只能用在` 里。
为什么你觉得`只能在宏里用，是因为大部分场合都是在宏里用导致你产生了错觉（宏本质就是返回一个列表）。此外'不支持, ,@
好的，正在学习中，所以会提一些入门问题。
\` is a Lisp macro in ‘backquote.el’.
`STRUCTURE
Argument STRUCTURE describes a template to build.
The whole structure acts as if it were quoted except for certain
places where expressions are evaluated and inserted or spliced in.
For example:
b => (ba bb bc) ; assume b has this value
`(a b c) => (a b c) ; backquote acts like quote
`(a ,b c) => (a (ba bb bc) c) ; insert the value of b
`(a ,@b c) => (a ba bb bc c) ; splice in the value of b
Vectors work just like lists. Nested backquotes are permitted.
;; When the Lisp reader sees `(...), it generates (\` (...)).
;; When it sees ,... inside such a backquote form, it generates (\, ...).
;; For ,@... it generates (\,@ ...).
;; This backquote will generate calls to the backquote-list* form.
;; Both a function version and a macro version are included.
;; The macro version is used by default because it is faster
;; and needs no run-time support. It should really be a subr.
From backquote.el
(evil-define-key 'insert vterm-mode-map (kbd "C-a") (lambda () (interactive) (vterm-send-string "\C-a")))
(evil-define-key 'insert vterm-mode-map (kbd "C-e") (lambda () (interactive) (vterm-send-string "\C-e")))
(evil-define-key 'insert vterm-mode-map (kbd "C-k") (lambda () (interactive) (vterm-send-string "\C-k")))
(evil-define-key 'insert vterm-mode-map (kbd "C-u") (lambda () (interactive) (vterm-send-string "\C-u")))
改成下面的写法，执行后vterm-send-string把key的值当中普通的字符串了
(dolist (key '("C-a" "C-e" "C-k" "C-u"))
(evil-define-key 'insert vterm-mode-map (kbd key)
`(lambda () (interactive) (vterm-send-string (concat "\\" ,key)))))
改成下面的写法，提示 Wrong type argument: listp, “^A”
(dolist (key-pair '(("C-a" . "\C-a") ("C-e" . "\C-e") ("C-k" . "\C-k") ("C-u" . "\C-u")))
(evil-define-key 'insert vterm-mode-map (kbd (car key-pair))
`(lambda () (interactive) (vterm-send-string (cdr ,key-pair)))))
OK了
;; 方法一
(dolist (key-pair '(("C-a" . "\C-a") ("C-e" . "\C-e") ("C-k" . "\C-k") ("C-u" . "\C-u")))
(evil-define-key 'insert vterm-mode-map (kbd (car key-pair))
`(lambda () (interactive) (vterm-send-string (cdr ',key-pair)))))
;; 方法二
(dolist (key-pair '(("C-a" "\C-a") ("C-e" "\C-e") ("C-k" "\C-k") ("C-u" "\C-u")))
(evil-define-key 'insert vterm-mode-map (kbd (car key-pair))
`(lambda () (interactive) (vterm-send-string (cadr ',key-pair)))))
通过这个例子，进一步理解`(backquote)这个宏的作用了。
为了更好的理解backquote，想简化成(dolist (key '("a" "e" "k" "u")) body)的样子，可以吗？
(define-key vterm-mode-map [f1] nil))
(define-key vterm-mode-map [f2] nil))
...
(define-key vterm-mode-map [f12] nil))
简化成下面的样子
(dolist (key '([f1] [f2] [f3] [f4] [f5] [f6] [f7] [f8] [f9] [f10] [f11] [f12]))
(define-key vterm-mode-map `,key nil))
上面的写法是正确的，进一步简化如下，但有问题，错在哪里？
(dotimes (n 12)
(let ((key (concat "[f" (int-to-string (1+ n)) "]")))
(define-key vterm-mode-map `,key nil)))
[f1]是个vector，不是字符串
你这个太逗了
是用来绑定F键
明天我改一下，把括号放在宏外面
谢谢 ～ 这回看懂了。 
哈哈哈 就是啊 在忙着过年呢
不错, 这个教程很好.
这个教程。。。没读懂，感觉停晦涩的，错别字，还有语法问题，看着很别扭
毕竟是 08 年左右写成，最近更新在 13 年的文章了。